Zigbee Addressing Example

Question:

Find the Address and Address Block for each device
RM = 2 , CM = 4, LM = 3
You can choose the Address of the Zigbee coordinator as ANC = 100

Solation:

We can use these formulas

Our values; RM = 2 , CM = 4 ve LM = 3

Cskip(d) = (1+4-2 -4 x 2^3-0-1)/1-2 = 13
We set our ANC which is 100 . ( Addr = 100 )

0.Level End Devices;

100+13×2 + 1 = 127
100+13×2 + 2 = 128

Routers;

Addr = 100+ 5x(1-1) + 1 = 101
Cskip(1) = (1+4-2-4×2^3-1-1)/1-2 = 5

Addr = 100+ 5x(2-1) + 1 = 106
Cskip(1) = (1+4-2-4×2^3-1-1)/1-2 = 5

1.Level Left End Devices

101 + 5×2 + 1 = 112
101 + 5×2 + 2 = 113

1.Level Right End Devices;

106 + 5×2 + 1 = 117
106 + 5×2 + 2 = 118

2.Level Left (Router)

Cskip(2) = (1+4-2-4×2^3-2-1)/1-2 = 1

Addr = 101+ 1x(1-1) + 1 = 102

2.Level Left (Router) End Devices

102 + 1×2+1 = 105
102 + 1×2+2 = 106
102+ 1×2+3 = 107
102+ 1×2+4 = 108

2.Level Left 2. Router

Cskip(2) = (1+4-2-4×2^3-2-1)/1-2 = 1

Addr = 101+ 1x(2-1)+ 1 = 103

2.Level Left 2. Router End Device

103 + 1×2+1 = 106
103 + 1×2+2 = 107
103 + 1×2+3 = 108
103 + 1×2+4 = 109

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2.Level Right 1. Router

Cskip(2) = (1+4-2-4×2^3-2-1)/1-2 = 1

Addr = 106+ 1x(1-1) + 1 = 107

2.Level Right 1. Router End Devices

107+ 1×2+1 = 110
107+ 1×2+2 = 111
107+ 1×2+3 = 112
107+ 1×2+4 = 113

2.Level Right 2. Router

Cskip(2) = (1+4-2-4×2^3-2-1)/1-2 = 1

Addr = 106+ 1x(1-1)+1 = 108

2.Level Right 2. Router End Devices

108+ 1×2+1 = 111
108+ 1×2+2 = 112
108+ 1×2+3 = 113
108+ 1×2+4 = 114